tag:blogger.com,1999:blog-4172814789229843414.post275723695575305666..comments2023-02-13T19:24:38.331+05:30Comments on Free Math Worksheets, Word Problems and Teaching Resources: Age Problems - Equations in single variable - AlgebraMr. Mathhttp://www.blogger.com/profile/12962099560219120967noreply@blogger.comBlogger25125tag:blogger.com,1999:blog-4172814789229843414.post-34027283921754549142013-04-18T08:58:44.651+05:302013-04-18T08:58:44.651+05:30I think you should put the answers to the problems...I think you should put the answers to the problems at the bottom so you can figure out how to solve it if you are stuck. Just the answers though. Nit the equations so you have to figure it out your self Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-30990818965087719142012-12-30T08:31:33.303+05:302012-12-30T08:31:33.303+05:30good site thanks for the help i dont feel so stupi...good site thanks for the help i dont feel so stupid now Chuck Testanoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-40831026442436709722012-12-16T07:54:58.403+05:302012-12-16T07:54:58.403+05:30How could his son be older than Pluto?How could his son be older than Pluto?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-7429934424238222422012-12-16T07:52:19.684+05:302012-12-16T07:52:19.684+05:30Ana=present,3x future, 3x + 4
Rain=present,x ...Ana=present,3x future, 3x + 4<br />Rain=present,x future, x + 4<br /><br />equation: 3x + 4 = 2(x + 4)<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-82799313065258281662012-09-02T21:32:44.395+05:302012-09-02T21:32:44.395+05:30This is awesome.This is awesome.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-49837195673969614902012-08-16T10:08:52.121+05:302012-08-16T10:08:52.121+05:30such a big helpsuch a big helpAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-80387777524609193442012-04-02T00:31:32.750+05:302012-04-02T00:31:32.750+05:30OMG this is so freaking awesomeOMG this is so freaking awesomeAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-62920840487464822992012-02-23T13:46:34.932+05:302012-02-23T13:46:34.932+05:30enricos father is now twice his age. In 20 years E...enricos father is now twice his age. In 20 years Enrico will be two thirds his fathers age then. How old is each now?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-15150556584999639442012-02-19T12:14:39.359+05:302012-02-19T12:14:39.359+05:30thank you
it helps me in my projectthank you<br />it helps me in my projectAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-85575097447495427852012-02-18T19:07:31.561+05:302012-02-18T19:07:31.561+05:30PLUTO IS 98 YRS OLD.HIS SON IS 62YRS OLDER THAN PL...PLUTO IS 98 YRS OLD.HIS SON IS 62YRS OLDER THAN PLUTO.FIND HIS SON'S AGE?ANONYMOUSnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-19788570453934646582012-01-12T20:09:05.638+05:302012-01-12T20:09:05.638+05:30Pls. answer this.
Ana is three times as old as Ra...Pls. answer this.<br /><br />Ana is three times as old as Rain. Four years from now she will be twice as old as rain. How old are they now? I need the Representation and the Solution. ThanksAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-90879869982364285672012-01-04T08:35:27.215+05:302012-01-04T08:35:27.215+05:30There was an error with question 17 and is correct...There was an error with question 17 and is corrected now. Please let me know in case of any doubt.Mr. Mathhttps://www.blogger.com/profile/12962099560219120967noreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-82997639498280169182012-01-04T06:23:15.021+05:302012-01-04T06:23:15.021+05:30Can you please explain to me question 17 on the pa...Can you please explain to me question 17 on the page on algebraic age problems? Thanks a lot!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-38884468986866778322012-01-03T14:14:32.390+05:302012-01-03T14:14:32.390+05:30,,great posts.. big help to math teachers.. tnx lo...,,great posts.. big help to math teachers.. tnx lotsAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-88846198373893330212011-12-17T14:02:49.979+05:302011-12-17T14:02:49.979+05:30Thank You help a lot for my exam =)Thank You help a lot for my exam =)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-90680453675684308542011-09-28T19:56:20.848+05:302011-09-28T19:56:20.848+05:30x/3 + x + (x+5) = 40
Multiplying every term by 3,...x/3 + x + (x+5) = 40<br /><br />Multiplying every term by 3, we have<br /><br />(x/3)*3 + x * 3 + (x+5) * 3 = 40 * 3<br /><br />x + 3x + 3x + 15 = 120<br /><br />7x + 15 = 120<br /><br />or<br /><br />x/3 + x + (x+5)<br /><br />This can be written as<br /><br />x/3 + x/1 + (x+5)/1<br /><br />Denominators are 3,1,1<br /><br />So, LCM = 3<br /><br />(x + x*3 + (x+5)*3)/3<br /><br />(x+3x+3x+15)/3<br /><br />(7x+15)/3<br /><br />Hope you understand this.Mr. Mathhttps://www.blogger.com/profile/12962099560219120967noreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-59630668082544538962011-09-28T18:17:04.115+05:302011-09-28T18:17:04.115+05:30i didnt get why the 2nd one becomes (7x+15)/3?????...i didnt get why the 2nd one becomes (7x+15)/3?????Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-26061890048335201702011-09-26T13:28:17.367+05:302011-09-26T13:28:17.367+05:30thank you i used it in my career examinationthank you i used it in my career examinationAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-42941002422945822942011-09-13T20:01:56.270+05:302011-09-13T20:01:56.270+05:30..it makes our assignments clearer!!..it makes our assignments clearer!!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-31026083069034921722011-08-07T16:07:11.317+05:302011-08-07T16:07:11.317+05:30will you please help me solve the problem number 4...will you please help me solve the problem number 4..thank youAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-73578087760106947642011-08-03T08:47:44.438+05:302011-08-03T08:47:44.438+05:30this helped me a lot!
thanks!
..........♥..........this helped me a lot!<br /><br />thanks!<br /><br />..........♥..............Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-61788313807702606692011-07-17T15:14:50.623+05:302011-07-17T15:14:50.623+05:30In four years, Donna's grandmother will be eig...In four years, Donna's grandmother will be eight times as old as Donna last year. When Donna's present age is added to his grandmother's present sge, the total is 72. How old is each one now?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-65534212683167180432011-02-22T19:01:52.284+05:302011-02-22T19:01:52.284+05:30Son's age = x
2 * Father's age = 8 + 6x
...Son's age = x<br /><br />2 * Father's age = 8 + 6x<br /><br />Divide by 2 on both sides<br /><br />Father's age = 4 + 3x<br /><br />Son's age (10 years ago) = x - 10 ....(1)<br />Father's age (10 years ago) = (4+3x)-10 <br /> = -6+3x .... (2)<br />Add equation (1) and (2, set it equals to 44 and solve for x.Mr. Mathhttps://www.blogger.com/profile/12962099560219120967noreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-75534966708878762902011-02-22T13:39:25.315+05:302011-02-22T13:39:25.315+05:30thank you so much..it helps me a lot..
can i ask a...thank you so much..it helps me a lot..<br />can i ask a favor?<br />can you show me how to solve this..it's confusing..and also show me an example in ratio form..<br /><br />Two times the father's age is 8 more than six times his son's age. Ten years ago, the sum of their ages was 44. The age of the son is:<br /><br />thank you so much..!:)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4172814789229843414.post-13182364319459721642011-02-17T19:21:24.080+05:302011-02-17T19:21:24.080+05:30Great Website..Thank You for the help provided !
:...Great Website..Thank You for the help provided !<br />:)Regards,<br />Well-wisherAnonymousnoreply@blogger.com